If `|vec a+vec b|=|vec a-vec b|`.Prove that the angle between `vec a` and `vec b` is `90^(@)`?

Define vec axx vec b and prove that | vec axx vec b|=( vec a. vec btantheta, where theta is the angle between vec a and vec b ) .

Two vectors vec(a) and vec(b) are such that |vec(a)+vec(b)|=|vec(a)-vec(b)| . What is the angle between vec(a) and vec(b) ?

If |vec(a)+vec(b)|ge|vec(a)-vec(b)| then angle between vec(a) and vec(b) may be

If vec a+ vec b+ vec c=0 and | vec a|=3,\ | vec b|=5 and | vec c|=7 , show that the angle between vec a and vec b is 60^0 .

If | vec a|=8,| vec b|=3 and | vec a x vec b|=12 , find the angle between vec a and vec bdot

The non-zero vectors are vec a,vec b and vec c are related by vec a= 8vec b and vec c = -7vec b . Then the angle between vec a and vec c is

If vec a and vec b are two vectors such that | vec a|=4,| vec b|=3 and vec a . vec b=6 . Find the angle between vec a and vec b .

If |vec(A)+vec(B)|=|vec(A)|=|vec(B)| then the angle between vec(A) and vec(B) is

If | vec a|+| vec b|=| vec c| and vec a+ vec b= vec c , then find the angle between vec a and vec bdot

If |vec(A)+vec(B)|=|vec(A)-vec(B)| , then find the angle between vec(A) and vec(B)