Match the column I and II. (Matrix)

Answer

`a- p, r, s; b - q, r; c- q, r; d-p, r, s`

Explanation

As shown in fig. the relation of dipole moment to configuration is quite direct. If in a 1, 2 -disubstituted alkene (XCH = CHY) X and Y are both electron donating or both electron withdrawing, the dipole moment of the cis isomer will generally be sizeable, whereas that of the trans isomer will be small or zero (i.e. `mu_("cis")gtmu_("trans")`). If, on the other hand, X is electron donating and Y is electron withdrawing, or vice versa, .`mu_("trans") gtmu_("cis")` . In tribustituted alkenes XCH = CYZ the situation is less clear cut, though if Z is alkyl and X and Y are halogen or other strongly electron withdrawing groups, the disposition (cis or trans)

of X and Y will be decisive. Except for the case of cyclooctene, configuration can be inferred from dipole moment where known, though in some cases the differences are perhaps uncomfortably small. In the case of 1-chloro-2-iodoethylene the original, seemingly unreasonable order of dipole moments was later reversed. In trans-cyclooctene, the normal `C_(2h)` symmetry of trans-XCH = CHX is reduced to at most `C_2`, therefore the compound can have a dipole moment, whereas compounds of `C_(2h)` symmetry cannot. That the moment is so large may be related to the highly twisted nature of the double bond (torsion angle between `136^@` and `157^@` )
Dipole Moments and the Dipole `"Rule"^(a)`:
As for as the question is concerned, melting point of (trans > cis)because trans form is more symmetrical than cis form.