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Calculate enantiomeric excees of mixture...

Calculate enantiomeric excees of mixture containing 6g of (+) 2-butanol and 4g of (-) -2-butanol.

A

`10% `

B

`20% `

C

`40% `

D

`33% `

Text Solution

Verified by Experts

The correct Answer is:
B
Optical purity or enantiomeric excess = `("Excess of one enantiomer")/("Total mixutre") xx 100 `
Enantiomeric excess (e. e.) = `(6g - 4g)/((6 + 4)) xx 100 = 20%`
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