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CH2 = CH – CH = CH – CH = CH2 How many...

`CH_2 = CH – CH = CH – CH = CH_2`
How many geometrical isomers are possible for this compound ?

A

2

B

3

C

4

D

8

Text Solution

Verified by Experts

The correct Answer is:
A

cis & trans across middle `pi`-bond.
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