How many geometrical isomers of this com...

How many geometrical isomers of this compound are possible ?

A

2

B

3

C

4

D

6

Verified by Experts

The correct Answer is:

B

Total geometrical isomers
` = 2^(n - 1) + 2^(n-1) p = n/2`
`= 2^1 + 2^@`
`= 3`

ISOMERISM (STRUCTURAL & STEREOISOMERISM)
MS CHOUHAN|Exercise LEVEL 2|66 Videos
ISOMERISM (STRUCTURAL & STEREOISOMERISM)
MS CHOUHAN|Exercise LEVEL 2 (SUBJECTIVE PROBLEMS)|17 Videos
HYDROCARBONS (ALKYNES)
MS CHOUHAN|Exercise Level -1|32 Videos
IUPAC NAME
MS CHOUHAN|Exercise LEVEL-2 (SUBJECTIVE PROBLEMS ) |1 Videos

Similar Questions

Explore conceptually related problems

CH_(3)-CH=C=C=CH-CH_(3) How many geometrical isomers of this triene are possible _____________

CH_3 - CH = C = C = CH_2 How many geometrical isomers of this triene are possible_____

CH_(3)-CH=underset(Br)underset(|)C-underset(Cl)underset(|)C=CH-CH_(3) Number of geometrical isomers possible for this compound are

CH_3 - CH =undersetoverset(|)( C)(C ) - undersetoverset(|)(C )(C ) = CH - CH_3 Number of geometrical isomers possible for this compound are

The possible number of geometrical isomers for this compound which can be isolated at room temperature is

How many geometrical isomers are possible for 2, 4-hexadiene?

How many geometrical isomers are possible for 2,4 heptadiene ?

With the molecular formula C_(2)FClBrI , how many geometrical isomers are possible?