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Ethyl acetoacetate when reacts with one ...

Ethyl acetoacetate when reacts with one mole methyl magnesium iodide then product of reaction will be :

A

`CH_(3)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-CH_(3)`

B

`{:(" "O^(ɵ)Moverset(o+)(g)Br" "O),(" |"" ||"),(CH_(3)-C-CH_(2)-C-CH_(3)),(" |"),(" "CH_(3)):}`

C

`CH_(3)-overset(O)overset(||)(C)-underset(overset(o+)(M)gBr)overset(ɵ)(CH_(2))-CO_(2)Et`

D

`CH_(2)^(-) -overset(O)overset(||)(C)-CH_(2)-CO_(2)Et`

Text Solution

Verified by Experts

The correct Answer is:
C

(because of active methylene group acid-base take place).
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