Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon.

Chlorine free radical make `1^(@), 2^(@), 3^(@)` radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive.
The relative rate of abstraction of hydrogen by Br is
`{:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):}`
The relative rate of abstraction of hydrogen by Cl is
`{:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):}`
1-halo-2, 3-dimethyl butane will be obtained in better yields, if halogen is :

Options

A. `Br_(2)`
B. `Cl_(2)`
C. `I_(2)`
D. Can't be predicted

Answer

B

Explanation

`Cl_(2)` is less selective `therefore 1^(@)` halide will be obtained in better yield.