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Vladimir Markovnikov rule : Alkenes unde...

Vladimir Markovnikov rule : Alkenes undergo electrophilic addition reactions. It is triggered by the acid acting as a electrophile toward t-electrons of the double bond. Markovnikov's rule states that when an unsymmetrically substituted alkene reacts with a hydrogen halide, the hydrogen atom adds to the carbon that has the greater number of hydrogen, e.g.,

Which of the following is most reactive toward Markovnikov addition ?

A

B

C

D

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The correct Answer is:
B
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Carbonyl compounds give different oxidation products with different reagents .Several oxidising agents can be used to oxidise carbonyy compounds .Ammonical silver nitate (tollens reagent ) oxidises aliphatic as well as aromatic aldehydes . R-CHO overset("Tollens reagents ") to R-COOh +Ag (silver mirror ) strong oxidatising agents like KMnO_4 //H^+ ,HNO_3 ,K_2 Cr_2 O_7 //H^+ oxidise Aldehydes as well as ketons . open chain ketons in oxidation give mixture of two carbonylic acids . oxidation as well as ketons of unsymmetrical ketons takes place according to popoff's rule .According to this rule alpha - carbon whose bond breaks in oxidation always belongs to the alkyl group which has more number of carbons which of the following is most reactive towards oxidation ?

Markovnikov addition takes place with unsymmetrical alkenes. The positive part of the reagent gets connected to the double bonded carbon with more number of hydrogens. In presence of peroxide and in special cases addition takes place against Markovnikov rule. 1-methyl cyclohenene on hydroboroation it will give

Electrophilic substitutions are characteristic reaction of aromatic compounds. In this reaction hydrogen of the aromatic ring is replaced by an electophile because hydrogen in the form of HR is very good leaving group. -COOH and -SO_3H are also good leaving groups when they are present either at ortho or at para to the highly activating groups like -NH_2 and -OH. Which one of the following compounds will be most unreactive towards electrophilic substitution reaction?

Markovnikov addition takes place with unsymmetrical alkenes. The positive part of the reagent gets connected to the double bonded carbon with more number of hydrogens. In presence of peroxide and in special cases addition takes place against Markovnikov rule. In which of the following compound addition takes place against Markovnikov rule

Addition of HX on alkene proceed through formation of carbocation . This reaction is follows Markovnikov's rule. According to markovnikov's rule addition of electrophile occurs on that carbon of alkene which have more number of -H atom Ph-CH = CH_2 underset(HX)to underset("(major)")(Ph-overset(x)overset(|)CH-CH_3) + underset("(minor)")(Ph-CH_2-CH_2-X) Which of the following alkenes will give markovnikov's reaction ?

Hydroboration is a reaction in which the boron hydride acts as an electrophile, R_2BH adds to a carbon - carbon double which acts as a nucleophile Organoborane compound The organoborane compound then is oxidised by treatment with hydrogen peroxide in aqueous sodium hydroxide to from alcohol. The OH group enters the carbon atom from the same side where the boron atom was present. Hence this reaction is highly regioselective and the boron atom attacheto that carbon atom which is less sterically hindred. Hydroboration oxidation and acid hydration will not give the same products in case of

Hydroboration is a reaction in which the boron hydride acts as an electrophile, R_2BH adds to a carbon - carbon double which acts as a nucleophile Organoborane compound The organoborane compound then is oxidised by treatment with hydrogen peroxide in aqueous sodium hydroxide to from alcohol. The OH group enters the carbon atom from the same side where the boron atom was present. Hence this reaction is highly regioselective and the boron atom attacheto that carbon atom which is less sterically hindred. Hydroboration oxidation and acid hydration will not give the same products in case of

Amines are less reactive in substitution reactions. Their reactivity is much lesser than alcohols and alkylflourides towards substitution. Protonation of the amino group makes it a better leaving group, but not nearly as good a leaving group as a protonated alcohol. Protonated amino groups cannot be displaced by OH^(-) because it would react immediately with the acidic hydrogen which would convert it in to a poor nucleophile. The leaving group in quartenary ammonium ion has about the same leaving tendency as a protonated amino group but does not have acidic hydrogen. The reaction of a quartenary ammonium ion with hydroxide ion is known as Hoffmann elimination reaction. The leaving group is tertiary amine. Since a tertiary amine is only a moderately good leaving group, the reaction requires heat. The carbon to which the tertiary amine is attached is designated as alpha carbon. When the hydroxide ion starts to remove a beta H from a quartenary ammonium ion, the leaving group does not immediately start to leave because a tertiary amine is not a good leaving group. As a result, a partial negative charge builds up on the carbon from which the proton is removed. Which of the following statements are true regarding Hoffmann elimination ?

MS CHOUHAN-HYDROCARBONS (ALKENES)-LEVEL-2
  1. In each reaction box write a single letter designating the best reagen...

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  2. Match the reagents a-j with products A-J. There is one best product fo...

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  3. Match the column :

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  4. Match the column I with column II and with column III (Matrix).

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  5. Match the column I and II.

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  6. Sum of molecular mass of A, B, C, D (i.e. A+B + C + D) is equal to :

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  7. underset("(all isomers) ")(C2FClBrl) underset(Ni) overset(H2)to (A)(ex...

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  8. Match the following columns

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  9. Vladimir Markovnikov rule : Alkenes undergo electrophilic addition rea...

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  10. Vladimir Markovnikov rule : Alkenes undergo electrophilic addition rea...

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  11. Vladimir Markovnikov rule : Alkenes undergo electrophilic addition rea...

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  12. Vladimir Markovnikov rule : Alkenes undergo electrophilic addition rea...

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  13. Vladimir Markovnikov rule : Alkenes undergo electrophilic addition rea...

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  14. Vladimir Markovnikov rule : Alkenes undergo electrophilic addition rea...

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  15. CH3 - CH2-CH=CH2+CH2 OH overset(H^(o+))to CH3-CH2- underset(OCH3) un...

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  16. CH3 - CH2-CH=CH2+CH2 OH overset(H^(o+))to CH3-CH2- underset(OCH3) un...

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  17. CH3 - CH2-CH=CH2+CH2 OH overset(H^(o+))to CH3-CH2- underset(OCH3) un...

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  18. CH3 - CH2-CH=CH2+CH2 OH overset(H^(o+))to CH3-CH2- underset(OCH3) un...

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  19. CH3 - CH2-CH=CH2+CH2 OH overset(H^(o+))to CH3-CH2- underset(OCH3) un...

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  20. Match the column I and II :

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