Fill in the blanks :
`1 - ( --- ) = cos^2theta`

Fill in the blanks: 1/2=""/20

( 1 + cos theta) ( 1 - cos theta ) cosec^2 theta =

Complete the following activity by filling the boxes sin^(2) theta+cos^(2) theta=square ……….(Identity) Dividing each term by cos^(2)theta (sin^(2)theta)/(cos^(2)theta)+(cos^(2)theta)/(cos^(2)theta)=(square)/(cos^(2)theta) :.square+1=square

sin ^ (4) theta + 2sin ^ (2) theta (1- (1) / (cos ec ^ (2) theta)) + cos ^ (4) theta =

((1 + sin theta-cos theta) / (1 + sin theta + cos theta)) ^ (2) = (1-cos theta) / (1 + cos theta)

1- (sin ^ (2) theta) / (1 + cos theta) + (1 + cos theta) / (sin theta) - (sin theta) / (1-cos theta) - (1) / (sec theta)

1+cos theta=2cos^(2)theta

If x= a sin 2theta (1+ cos 2theta) , y= b cos 2theta(1- cos 2theta) , then (dy)/(dx) =

Fill in the blanks with refrence to the figure given below . i. sin theta = ii. cos theta = iii. tan theta =