Given function is `f: R=>R, f(x) = x^2+1`. If `A={10,37}`, then what is the value of `f^(-1)A`?

If f(x)=4x-x^2, x in R , then write the value of f(a+1)-f(a-1)dot

Let f: R->R be a continuous function and f(x)=f(2x) is true AAx in R . If f(1)=3, then the value of int_(-1)^1f(f(x))dx is equal to

The function f:R to R given by f(x)=x^(2)+x is

If function f : R rarr R^(+), f(x) = 2^(x) , then f^(-1) (x) will be equal to

Let f:R→R:f(x)=x ^2+1 . find f^(−1) {10}

A function f :Rto R is defined as f (x) =3x ^(2) +1. then f ^(-1)(x) is :

A function f :Rto R is defined as f (x) =3x ^(2) +1. then f ^(-1)(x) is :

Let f: R → R be a one-one onto differentiable function, such that f(2)=1 and f^(prime)(2)=3. Then, find the value of (d/(dx)(f^(-1)(x)))_(x=1)

A function f: R to R is defined as f(x)=4x-1, x in R, then prove that f is one - one.

A function f is defined by f(x)=1/(2^(r-1)),1/(2^r)ltxlt=1 (2^(r-1)),r="1,2,3 then the value of int_0^1f(x)dx