`5(2x+1)(3x+5)div(2x+1)`

If 5 ^(2x +1) div 25 = 125, find the value of x .

Let the equation x^(5) + x^(3) + x^(2) + 2 = 0 has roots x_(1), x_(2), x_(3), x_(4) and x_(5), then find the value of (x_(2)^(2) - 1)(x_(3)^(2) - 1)(x_(4)^(2) - 1)(x_(5)^(2) - 1).

2[(1)/(2x + 1) + (1)/(3(2x + 1)^(3)) + (1)/(5(2x + 1)^(5)) + (1)/(5(2x + 1)^(5)) + …] is equal to ,

Add :5x^(2)-(1)/(3)x+(5)/(2),-(1)/(2)x^(2)+(1)/(2)x-(1)/(3) and -2x^(2)+(1)/(5)x-(1)/(6)

solve for x (2x-5)/(3x-1)=(2x-1)/(3x+2)

(2x^2-3x+2x^4)div(x^2-1)

If |{:( 2x, x + 3),(2 (x +1), x +1):}| = |{:(3,3),( 1, 5):}|, then the value of x is :

(2x + 3) / (2x + 5)-(x) / (x + 1) = (1) / (2x + 3), (x! = -1, x! =-(5) / (2) , x! =-(3) / (2))