What is the sum of x, y and z?
`x + y = 8`
`x + z = 11`
`y + z = 7`

For 0 < varphigeqpi/2,ifx=sum_(n=0)^oocos^(2n)varphi,y=sum_(n=0)^oosin^(2n)varphi,t h e n (a) x y z=x z+y (b) x y z=x y+z (c) x y z=x+y+z (d) x y z=y z+x

If x =a, y=b, z=c is a solution of the system of linear equations x + 8y + 7z =0, 9 x + 2y + 3z =0, x + y+z=0 such that point (a,b,c ) lies on the plane x + 2y + z=6, then 2a+ b+c equals

The lines x + y + z - 3 = 0 = 2x - y + 5z - 6 and x - y - z + 1 = 0 = 2x + 3y + 7z - k are coplanar then k equals

Add the following: (i) x – 3y – 2z , 5x + 7y – 8z , 3x – 2y + 5z

Add : 8x - 3y + 7z, -4x + 5y - 4z, -x - y - 2z

Subtract the sum of 13 x-4y+7z and -6z+6x+3y from the sum of 6x-4y-4z and 2x+4y-7.

If x,y and z are positive integers such that x < y < z and x + y + z = 6 , then what is the value of z?

Value of |[x+y, z,z ],[x, y+z, x],[y, y, z+x]|, where x ,y ,z are nonzero real number, is equal to a. x y z b. 2x y z c. 3x y z d. 4x y z

If x = 10a, y = 3b , z = 7c and x : y : z = 10 : 3 : 7 , then (7x + 2y + 5z)/(8a + b + 3c) =

Subtract 12x + 3y - z from the sum of 7x + 4y - 5z + 5 and 6x - 7z - 8 .