Let `f(x)={(1+|x-2|, ,x!=2), (2, , x=2):}` then at `x=2, f(x)` has

Let f(x)=|x-2| , then

If f(x)={((x-2)2^(-(1/(|x-2|)+1/(x-2))),x!=2),(0,x=2):} then f(x) at x=2 is

Let f(x)=x^3-6x^2+12x-3 . Then at x=2 f(x) has

Let f(x)={{:(3x^2-2x+10, x lt 1),(-2,x gt 1):} The set of values of b for which f(x) has greatest value at x=1 is

If f(x)={{:(,(|x+2|)/(tan^(-1)(x+2)),x ne -2),(,2, x=-2):} , then f(x) is

Let f(x) = tan^(-1)(((x-2))/(x^(2)+2x+2)) ,then 26 f'(1) is

Let f(x)=(x^(2))/(1-x^(2)),xne0,+-1 , then derivative of f(x) with respect to x, is

Let f(x) =x^(2) , x in (-1,2) Then show that f(x) has exactly one point of local minima but global maximum Is not defined.

let f(x)=sqrt(1+x^2) then

Let f'(x) = sin(x^2) and y = f(x^2 +1) then dy/dx at x=1 is