[(1+cos""(theta/2)-isin""(theta/2))/(1+c...

`[(1+cos""(theta/2)-isin""(theta/2))/(1+cos""(theta/2)+isin""(theta/2))]^(4n)` का मान है :

A

`cosntheta -isinntheta`

B

`cosntheta +isinntheta`

C

`cos2ntheta -isinn2ntheta`

D

`cosn2ntheta +isinn2ntheta`

लिखित उत्तर

Verified by Experts

The correct Answer is:

C

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