`I=int e^(mtan^-1x)/(1+x^(2))dx`

inte^(mtan^-1x)/(1+x^2)^2dx

Evaluate inte^(mtan^-1x)/(1+x^2)^(3/2)dx

(i) int(1)/((1+x^(2))tan ^(-1) x )dx " "(ii) int(e^(tan^(-1)x))/(1+x^(2))dx

Evaluate: (i) int((sin(log x))/(x)dx (ii) int(e^(m)tan(-1)x)/(1+x^(2))dx

int(e^(mtan^(-1)x))/((1+x^(2)))dx

" (i) "int(e^(tan^(-1)x)dx)/((1+x^(2))

int e^(x)((1-x)/(1+x^(2)))^(2)dx

(1). int e^(x)((2-x)/((1-x)^(2)))dx (2). int e^(x)((x-1)^2/((x^2+1)^(2)))dx

Integrate the following functions (i) int((1+x)^(4))/(x)dx (ii) int(e^(200x)+e^(202x))/(e^(x)+e^(-x))dx (iii) int(1+tan^(2)x)/(1+cot^(2)x)dx

(i) int (e^(x) .(1-x))/(x^(2))dx (ii) int ((1+sin x)/(1+cos x))e^(x) dx