3x+2y=1, 6x+4y=

3x-y=8-x 6x+4y=2y-9 For the system of equations above, what is the value of the product xy?

Do the following pair of linear equations have no solution ? Justify your answer. (i) 2x + 4y = 3 and 12y +6x = 6 (ii) x = 2y and y = 2x (iii) 3x + y - 3 = 0 and 2x + (2)/(3)y = 2

If 3x+2y=12 and x y=6 , find the value of 9x^2+4y^2

If 3x+2y=12 and x y=6, find the value of 9x^2+4y^2

Test the consistency of the following system of equations : (i) 3x-y=2 ,6x-2y=4 (ii) x+5y=1 , 2x+2y=4 (iii) 2x-z=-1, 6x-6y-2z=5 , 3x-y-2z=2

In each of the following systems of equations determine whether the system has a unique solution, no solution or infinitely many solutions. In case there is a unique solution, find it. (1) 2x+3y=7 , 6x+5y=11 (2) 6x+5y=11 , 9x+(15)/2y=21 (3) -3x+4y=5 , 9/2x-6y+(15)/2=0

{:(3x - y = 2),(6x + 2y = 4):}

Prove that the centres of the circles x^2+y^2=1 , x^2+y^2+6x-2y-1=0 and x^2+y^2-12x+4y=1 are collinear

Prove that the centres of the circles x^2+y^2=1 , x^2+y^2+6x-2y-1=0 and x^2+y^2-12x+4y=1 are collinear

If |(x, x+y, x+y+z),(2x,3x+2y, 4x+3y+2z),(3x,6x+3y, 10x+6y+3z)|=64 then the real value of x is