For triangle ABC, show that: `sin((A+B)/(2))-cos(C)/(2)=0`

For triangle ABC, show that : (i) "sin" (A + B)/(2) = "cos" (C)/(2) (ii) "tan" (B + C)/(2) = "cot" (A)/(2)

If A, B and C are interior angles of a triangle ABC, then show that "sin"((B+C)/2)=cos(A/2) .

For triangle ABC, show that "tan"(B+C)/2="cot"A/2

If A, B and C are interior angles of a triangle ABC, then show that "sin"((B+C)/2)=cosA/2 .

In any triangle ABC, show that : 2a cos (B/2) cos (C/2) = (a+b+c) sin (A/2)

In any triangle ABC, show that : 2a sin (B/2) sin (C/2)=(b+c-a) sin (A/2)

For any triangle ABC, prove that (a-b)/c=(sin((A-B)/2))/(cos(C/2))

if A, B and C are interior angles of a triangle ABC, then show that cos((B+C)/2) = sin (A/2)

if A, B and C are interior angles of a triangle ABC, then show that cos((B+C)/2) = sin (A/2)

For any triangle ABC, prove that (b+c)cos((B+C)/2)=acos((B-C)/2)