6 + `log_(1/4) (1/sqrt(2))[sqrt(1-(1/sqrt(2))sqrt(1-(1/sqrt(2))sqrt(1-(1/sqrt(2)))]`

The value of 6+log_((3)/(2))((1)/(3sqrt(2))sqrt(4-(1)/(3sqrt(2))sqrt(4-(1)/(3sqrt(2))sqrt(4-(1)/(3sqrt(2))...cdots))))

The value of 6+ log_(3//2) (1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...)))) is ________.

The value of 6+log_(3//2)(1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)sqrt(4-1/(3sqrt2)...)))) is

The value of log_((9)/(4))((1)/(2sqrt(3))sqrt(6-(1)/(2sqrt(3))sqrt(6-(1)/(2sqrt(3))sqrt(6-(1)/(2sqrt(3)))))...oo) is

(1)/(sqrt(2)+sqrt(3))+(1)/(sqrt(3)+sqrt(4))

log_((sqrt(2)+1))(sqrt(2)-1)=

(1)/(sqrt(7)-sqrt(2))-(1)/(sqrt(7)+sqrt(2))=

x=(1)/(1+sqrt(2))+(1)/(sqrt(2)+sqrt(3))+(1)/(sqrt(3)+2)=

(1)/(sqrt(2)+sqrt(3))-(sqrt(3)+1)/(2+sqrt(3))+(sqrt(2)+1)/(2+2sqrt(2))