RMS Current & Voltage |AC EMF Across (Resistor, Capacitor, Inductor) |Reactance vs Angular Velocity |AC EMF Across R-C Circuit

An LCR series circuit is connected to an oscillator (AC supply) having RMS voltage 200 V. If the RMS voltages across resistor, inductor and capacitor are equal, then RMS voltage across the resistor would be

In the LCR circuit shown,if RMS voltages across resistor inductor and capacitor are equal,the RMS value of voltage across resistor will be

A 50 Omega resistor an inductor and a capacitor are connected to an AC source 220 V. The frequency of source is 50 Hz. Calculate the current in the circuit if voltage across resistor capacitor and inductor is 220 V, 260 V and 260 V, respectively.

STATEMENT-1: In a series LCR circuit at resonance, the voltage across the capacitor or inductor may be more than the applied voltage. STATEMENT-2: At resonance in a series LCR circuit, the voltages across inductor and capacitor are out of phase.

In the given circuit the R.M.S values of voltages across the capacitor C, inductor L and resistor R_(1) are 12V, 10V and 5 V respectively. Then the peak voltage across R_(2) is

An ac voltmeter with large impedance is connected in turn across the inductor, the capacitor, and the resistor in a series circuit having an alternating emf of 125 V (rms), the meter gives the same reading in volts in each case. What is this reading?

In a series RC circuit connected across an AC source of 220 V 50 Hz calculate the rms voltage across resistor and capacitor if values of R and C are 100 Omega and 20 μF respectively .

A high impedance AC voltmeter is connected in turn across the inductor, the capacitor and the resistor in a series circuit having an AC source of 100 V (rms) and gives the same reading in volts in each case. This reading is:

If A.C. voltage is applied to a pure capacitor, then votage across the capacitor ………….. .

In the series L-C-R circuit shown in the figure, the rms voltage across the resistor and inductor are 400 V and 700 V respectively. If the applied voltage is E=500sqrt(2)sin(omega t) , then the peak voltage across the capacitor is