Home
Class 12
MATHS
34. The area of a trapezium is defined b...

34. The area of a trapezium is defined by function f and given by `f(x)=(10+x)sqrt(100-x^2)` ,then the area when it is maximised is
(a)75 `cm^2`
(b) `7sqrt(3) cm^2 `
(c) `75sqrt(3) cm^2 `
(d) `5 cm^2`

Promotional Banner

Similar Questions

Explore conceptually related problems

The domain of the function f defined by f(x)= sqrt(x^(2)-9) is

If f is a real function defined by f(x)=(log(2x+1))/(sqrt3-x) , then the domain of the function is

Let D be the domain of the real valued function f defined by f(x)=sqrt(25-x^(2)) . Then, write D.

Find the domain of the function f(x) defined by f(x)=sqrt(4-x)+1/(sqrt(x^2-1)) .

Find the domain of the function f(x) defined by f(x)=sqrt(4-x)+1/(sqrt(x^2-1)) .

The three sides of a trapezium are equal, each being 8cm. The area of the trapezium, where it is maximum, is (a) 24sqrt(3) c m^2 (b) 48sqrt(3)c m^2 (c)72 sqrt(3)c m^2 (d) none of these

The domain of the function f defined by f(x)= sqrt(a-x)+(1)/( sqrt(x^(2)-a^(2)) is

Each side of an equilateral triangle is 8 cm. Its area is (a) 16sqrt(3)\ c m^2 (b) 32sqrt(3)\ c m^2 (c) 24sqrt(3)\ c m^2 (d) 8sqrt(3)\ c m^2

The function f(x)=log_(10)(x+sqrt(x^(2))+1) is

The domain of the function f(x)=sqrt(x-sqrt(1-x^2)) is