`[[cos(pi)/(5)-i sin(pi)/(5)]]^(-5)`

answer the questions an instructed. Modulus of ("cos"(5pi)/(3)-i "sin"(pi)/(6)) is

For a complex number z, if arg(z) in (-pi, pi], then arg(1+cos.(6pi)/(5)+I sin.(6pi)/(5)) is (here i^(2)-1 )

Covert the complex number z = 1 + cos (8pi)/(5) + i. sin (8pi)/(5) in polar form. Find its modulus and argument.

sin^(-1)sin((3pi)/5)

sin "" (pi)/(5) sin "" (2pi)/(5) sin ""(4pi)/(5) sin""(3pi)/(5) = (5)/(16).

The principal value of arg (z) , where z=1+cos((8pi)/5)+i sin((8pi)/5) (where, i=sqrt-1) is given by

sin^(-1)(sin (3 pi)/(5))

Find the value of cos""(pi)/(12)(sin""(5pi)/(12)+cos""(pi)/(4))+sin""(pi)/(12)(cos""(5pi)/(12)-sin""(pi)/(4)) .

Prove that: 15sin(5pi)/(12)+15cos(5pi)/(12)-20sin^3(5pi)/(12)-20cos(5pi)/(12)=0

The amplitude of sin (pi)/(5) +i(1-cos"" (pi)/(5)) is