If 0.5 moles of`BaCl_(2)` is mixed with 0.2 moles of `Na_(3)PO_(4)`the maximum amount of `Ba_(3)(PO_(4))_(2)` that can be formed is :

If 0.5 mole of BaCl_(2) is mixed with 0.20 mole of Na_(3)PO_(4) , the maximum number of Ba_(3)(PO_(4))_(2) that can be formed is :

If 0.50 mol of BaCl_(2) is mixed with 0.20 mol of Na_(3)PO_(4) , the maximum number of moles of Ba_(3)(PO_(4))_(2) that can be formed is

Ca_(3)(PO_(4))_(2) is :

Ca_(3)(PO_(4))_(2) is :

If 0.5 mol of CaBr_(2) is mixed with 0.2 mol of K_(3) PO_(4) , the maximum nubmer of moles of Ca_(3) (PO_(4))_(2) that can be formed is: a. 0.1 b. 0.2 c. 0.5 d.0.7

If 0.5 mole of BaCl_(2) mixed with 0.20 mole of Na_(3) PO_(4) the maximum number of moles of Ba_(3)(PO)_(2) then can be formed is

0.5 mole of H_(2)SO_(4) is mixed with 0.2 mole of Ca(OH)_(2) . The maximum number of mole of CaSO_(4) formed is:

Ca_(3)(PO_(4))_(2) is presents in bones.

How many moles of Na^(+) ions are in 20mL "of" 0.40" "M " "Na_(3)PO_(4) .

50 g of CaCO_(3) is allowed to react with 70 g of H_(3)PO_(4^(.) Calculate : (i) amount of Ca_(3)(PO_(4))_(2) formed (ii) amount of unreacted reagent