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The limiting molar conductivities overse...

The limiting molar conductivities `overset(o)(wedge)` for NaCl, KBr and KCl are 126, 152 and `150 S cm^(2)mol^(-1)` respectively. The `overset(o)(wedge)` for NaBr is:

A

`128 S cm^(2) mol^(-1)`

B

`278 S cm^(2) mol^(-1)`

C

`976 S cm^(2) mol^(-1)`

D

`302 S cm^(2) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`lamda_(NaBr)= lamda NaCl + lamda KBr - lamda KCl`
`lamda_(NaBr)= 126+ 152- 150= 128 S cm^(2) mol^(-1)`
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