How much electricity in terms of Faraday is required to produce 100 g of Ca from molten `CaCl_2` ?

Options

A. 1F
B. 2F
C. 3F
D. 5F

Answer

D

Explanation

One mole of electron charge is equivalent to one Faraday.
Given reaction,
`CaCl_(2) rarr Ca^(2+) + 2Cl^(-)`
Ca is undergoing oxidation i.e., `Ca^(2+) + 2e^(-) rarr Ca`
We can observe that 40g of Ca takes `2e^(-)` charge,
So, 1 mole of Ca(40g) = 2F
Now, 100g of Ca = 5F