Formation of alkanes by the action of zinc on alkyl halide is called:

Options

A. Wurtz reaction
B. Canninzzaro's reaction
C. Claisen reaction
D. Frankland Reaction

Explanation

To solve the question regarding the formation of alkanes by the action of zinc on alkyl halides, we can follow these steps:

### Step-by-step Solution:

1. **Identify the Reaction**: The question asks about the formation of alkanes through the action of zinc on alkyl halides. This reaction involves the reduction of alkyl halides.

2. **Write the General Reaction**: The general reaction can be represented as:
\[ 2 \text{R-X} + \text{Zn} \rightarrow \text{R-R} + \text{ZnX}_2 \]
Here, R represents the alkyl group, X is the halogen, and Zn is zinc.

3. **Example of Alkyl Halide**: Let's take ethyl chloride (C2H5Cl) as an example of an alkyl halide:
\[ 2 \text{C}_2\text{H}_5\text{Cl} + \text{Zn} \rightarrow \text{C}_4\text{H}_{10} + \text{ZnCl}_2 \]
This shows that two moles of ethyl chloride react with zinc to form butane (C4H10) and zinc chloride (ZnCl2).

4. **Identify the Type of Reaction**: This reaction is specifically known as the **Frankland Reaction**. It is characterized by the coupling of alkyl halides in the presence of zinc.

5. **Conclusion**: Therefore, the answer to the question is that the formation of alkanes by the action of zinc on alkyl halides is called the **Frankland Reaction**.

### Final Answer:
The formation of alkanes by the action of zinc on alkyl halides is called the **Frankland Reaction**.