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Which white precipitate is soluble in ex...

Which white precipitate is soluble in excess `NH_(4)OH`.....

A

NaCl

B

AgCl

C

`Mg(OH)_(2)`

D

`NaOH`

Text Solution

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The correct Answer is:
To determine which white precipitate is soluble in excess NH₄OH (ammonium hydroxide), we need to analyze the behavior of common white precipitates when treated with NH₄OH. ### Step-by-Step Solution: 1. **Identify Common White Precipitates**: - The common white precipitates include AgCl (silver chloride), Ba(OH)₂ (barium hydroxide), PbCl₂ (lead(II) chloride), and Mg(OH)₂ (magnesium hydroxide). 2. **Consider the Reaction with NH₄OH**: - NH₄OH can react with certain metal ions to form soluble complexes. Not all white precipitates will react in this way. 3. **Analyze Each Precipitate**: - **AgCl**: Silver chloride is a white precipitate that is insoluble in water but can dissolve in excess NH₄OH due to the formation of a complex ion, [Ag(NH₃)₂]⁺. - **Ba(OH)₂**: Barium hydroxide is soluble in water and does not form a precipitate with NH₄OH. - **PbCl₂**: Lead(II) chloride is slightly soluble in cold water and can dissolve in hot water but does not form a complex with NH₄OH. - **Mg(OH)₂**: Magnesium hydroxide is also insoluble in water and does not react with NH₄OH to form a soluble complex. 4. **Conclusion**: - The only white precipitate that is soluble in excess NH₄OH is **AgCl** (silver chloride), as it forms a soluble complex with the ammonia present in NH₄OH. ### Final Answer: The white precipitate that is soluble in excess NH₄OH is **AgCl (silver chloride)**. ---
To determine which white precipitate is soluble in excess NH₄OH (ammonium hydroxide), we need to analyze the behavior of common white precipitates when treated with NH₄OH. ### Step-by-Step Solution: 1. **Identify Common White Precipitates**: - The common white precipitates include AgCl (silver chloride), Ba(OH)₂ (barium hydroxide), PbCl₂ (lead(II) chloride), and Mg(OH)₂ (magnesium hydroxide). 2. **Consider the Reaction with NH₄OH**: ...
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