Choose the correct balanced chemical equations to show the reactions of the following:
Action of sodium hydroxide on freshly precipitated aluminium hydroxide.

Options

A. `Al(OH)_(3) + NaOH rarr NaAlO_(2) + 2H_(2)O`
B. `Al(OH)_(3) + NaOH rarr NaAlO + 2H_(2)O`
C. `Al(OH)_(3) + NaOH rarr NaAlO_(2) + 2H_(2)`
D. `Al(OH)_(3) + NaOH rarr NaAlO_(2) + 2OH`

Explanation

To solve the question regarding the action of sodium hydroxide on freshly precipitated aluminum hydroxide, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Sodium hydroxide (NaOH)
- Freshly precipitated aluminum hydroxide (Al(OH)₃)

### Step 2: Understand the Nature of the Reactants
- Sodium hydroxide is a strong base.
- Aluminum hydroxide is amphoteric, meaning it can react with both acids and bases.

### Step 3: Write the Reaction
When aluminum hydroxide reacts with sodium hydroxide, it acts as an acid and forms sodium aluminate (NaAlO₂) and water (H₂O). The balanced chemical equation for this reaction is:

\[ \text{Al(OH)}_3 (s) + \text{NaOH} (aq) \rightarrow \text{NaAlO}_2 (aq) + \text{H}_2\text{O} (l) \]

### Step 4: Balance the Equation
Now, let's ensure that the equation is balanced:
- On the left side, we have:
- 1 Aluminum (Al)
- 4 Hydroxide (OH) groups (3 from Al(OH)₃ and 1 from NaOH)

- On the right side, we have:
- 1 Aluminum (Al) in NaAlO₂
- 2 Oxygen from NaAlO₂ and 1 from H₂O, totaling 3 Oxygens.
- 1 Sodium (Na) from NaAlO₂
- 2 Hydrogens from H₂O.

The equation is balanced as written.

### Final Balanced Equation
\[ \text{Al(OH)}_3 (s) + \text{NaOH} (aq) \rightarrow \text{NaAlO}_2 (aq) + \text{H}_2\text{O} (l) \]

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