`(sqrt5-sqrt3)^2=?`

(sqrt5 - sqrt 3)^2

(sqrt(5)-sqrt(2))(sqrt(2)-sqrt(3)) (sqrt(5)-sqrt(3))^(2)

(sqrt(5)-sqrt(2))(sqrt(2)-sqrt(3)) (sqrt(5)-sqrt(3))^(2)

(sqrt(5)-sqrt(2))(sqrt(2)-sqrt(3)) (sqrt(5)-sqrt(3))^(2)

Simplify the following expressions: (sqrt(3)+sqrt(7))^(2)( ii) (sqrt(5)-sqrt(3))^(2)(2sqrt(5)+3sqrt(2))^(2)

(1+sqrt2)/(sqrt5+sqrt3)= ((1+sqrt2)xx(sqrt5-sqrt3))/((sqrt5+sqrt3)xx(sqrt5-sqrt3))=

Evaluate (sqrt(5)-sqrt(3))/(sqrt(2)+sqrt(7))

Rationalise the denominator of : (i)(5)/(3+sqrt(5)-2sqrt(2))" "(ii)(2)/(sqrt(5)+sqrt(3)+2)

Simplify ((sqrt(5)-sqrt(3))(sqrt(5)+sqrt(3)))/((sqrt(5)+2)+(2-sqrt(5)))