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nidentical cells each of EMF E and inter...

nidentical cells each of EMF E and internal resistance r are connected in series. An external resistance R is connected in series to the combination. The current through R is

A

`(nE)/(R+nr)`

B

`(nE)/(nR+r)`

C

`E/(R+nr)`

D

`(nE)/(R+r)`

Text Solution

Verified by Experts

The correct Answer is:
B
`("nE")/(nR+r)`
Explanation : n identical cells each of e.m.f .E and internal resistance r are in parallel and connected in series with R.
Then , `i = E/(R+r/n) " " [ :. 1/(r_("total")) =1/r +1/r +1/r ...." n times "= n/r, r_("total")=r/n]`
` i =(nE)/(nR+r)`
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