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The SI unit of magnetic permeability is...

The SI unit of magnetic permeability is

A

`"kg"ms^(-2)A^(-2)`

B

`"kg "mm^(2)s^(-2)A^(-2)`

C

`"kg "m^(2)s A^(-2)`

D

`" kg "ms^(2)A^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`"kg.m.sec"^(-2)A^(-2)`
Explanation :We know that the force per unit length acting between two wire .
`F/l =(mu_(0))/(4pi). (2I_(1)I_(2))/r`
`mu_(0)=(F.4pi.r)/(l.2I_(1)I_(2))=(kg. m/(sec^(2)).m)/(m.A.A) = kg. sec^(-2)A^(-2)`
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