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An alternating e.m.f of 100 V is placed ...

An alternating e.m.f of 100 V is placed is applied to a circuit containing a resistance of `40 Omega ` and an inductance L in series . The current is found to lag behind the voltage by an angla a = `tan^(-1) 3//4`
The impedance of the circuit is :

A

`40 Omega`

B

`30 Omega`

C

`50 Omega`

D

`10sqrt(5) Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`50 Omega`
Explanation : Impedance of the circuit , `Z= sqrt(R^(2)+X_(L)^(2))`
`sqrt(40^(2)+30^(2))" " ( :. X_(L)=30 Omega)`
`= 50 Omega `
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