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An AC source of voltage E = 30 sin 100 t...

An AC source of voltage E = 30 sin 100 t is connected across a resistance `30Omega` The RMS value of current in the circuit will be:

A

`1/2A`

B

`1A`

C

`1/sqrt2A`

D

`sqrt2A`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_0 = 30 V and R = 30 Omega`
`I_0 = E_0/R=(30 V)/(30 Omega) = 1V`
RMS value of current in the circuit `I_(rms)=I_0/sqrt2`
`:. I_(rms)=I_0/sqrt2A`
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