A sinusoidal voltage of peak value 210 V and angular frequency 300/s is applied to a series LCR circuit. Given that `R-5Omega, L-25` mH and `C - 1000 muF`.
Calculate the capacitive reactance.

Options

A. `2.3 Omega`
B. `3.3 Omega`
C. `3.5 Omega`
D. `4.3 Omega`

Explanation

To calculate the capacitive reactance (Xc) in a series LCR circuit, we can use the formula:

\[ X_c = \frac{1}{\omega C} \]

where:
- \( \omega \) is the angular frequency,
- \( C \) is the capacitance.

### Step-by-Step Solution:

1. **Identify the given values**:
- Angular frequency \( \omega = 300 \, \text{s}^{-1} \)
- Capacitance \( C = 1000 \, \mu F = 1000 \times 10^{-6} \, F = 1 \times 10^{-3} \, F \)

2. **Substitute the values into the formula**:
\[ X_c = \frac{1}{\omega C} = \frac{1}{300 \times (1 \times 10^{-3})} \]

3. **Calculate the denominator**:
\[ 300 \times (1 \times 10^{-3}) = 0.3 \]

4. **Calculate \( X_c \)**:
\[ X_c = \frac{1}{0.3} \approx 3.33 \, \Omega \]

5. **Round the result**:
\[ X_c \approx 3.3 \, \Omega \]

### Final Answer:
The capacitive reactance \( X_c \) is approximately \( 3.3 \, \Omega \).