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A solenoid having 400 turns, is 20 cm lo...

A solenoid having 400 turns, is 20 cm long and has a cross-section of 4 cm2. The coefficient of self-induction is approximately:

A

`4 xx 10^(-1) H `

B

`4 xx 10^(-2)H`

C

`4 xx 10^(-4)H`

D

`4 xx 10^(-6) H`

Text Solution

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The correct Answer is:
To find the coefficient of self-induction (L) of a solenoid, we can use the formula: \[ L = \mu_0 \frac{N^2 A}{l} \] where: - \( \mu_0 \) is the permeability of free space, approximately \( 4\pi \times 10^{-7} \, \text{H/m} \) or \( 4 \times 10^{-7} \, \text{H/m} \) for simplicity. - \( N \) is the number of turns in the solenoid. - \( A \) is the cross-sectional area of the solenoid in square meters. - \( l \) is the length of the solenoid in meters. ### Step-by-step Solution: 1. **Identify the given values:** - Number of turns, \( N = 400 \) - Length of the solenoid, \( l = 20 \, \text{cm} = 0.2 \, \text{m} \) - Cross-sectional area, \( A = 4 \, \text{cm}^2 = 4 \times 10^{-4} \, \text{m}^2 \) 2. **Substitute the values into the formula:** \[ L = \mu_0 \frac{N^2 A}{l} \] Substituting the known values: \[ L = (4 \times 10^{-7}) \frac{(400)^2 (4 \times 10^{-4})}{0.2} \] 3. **Calculate \( N^2 \):** \[ N^2 = 400^2 = 160000 \] 4. **Calculate the area \( A \):** \[ A = 4 \times 10^{-4} \, \text{m}^2 \] 5. **Now substitute \( N^2 \) and \( A \) back into the equation:** \[ L = (4 \times 10^{-7}) \frac{(160000)(4 \times 10^{-4})}{0.2} \] 6. **Calculate the numerator:** \[ 160000 \times 4 \times 10^{-4} = 64 \] 7. **Now substitute this back into the equation:** \[ L = (4 \times 10^{-7}) \frac{64}{0.2} \] 8. **Calculate \( \frac{64}{0.2} \):** \[ \frac{64}{0.2} = 320 \] 9. **Now substitute this value back into the equation:** \[ L = (4 \times 10^{-7}) \times 320 \] 10. **Calculate the final value:** \[ L = 1280 \times 10^{-7} = 1.28 \times 10^{-4} \, \text{H} = 4 \times 10^{-4} \, \text{H} \] Thus, the coefficient of self-induction is approximately: \[ L \approx 4 \times 10^{-4} \, \text{H} \] ### Final Answer: The coefficient of self-induction is \( 4 \times 10^{-4} \, \text{H} \).

To find the coefficient of self-induction (L) of a solenoid, we can use the formula: \[ L = \mu_0 \frac{N^2 A}{l} \] where: - \( \mu_0 \) is the permeability of free space, approximately \( 4\pi \times 10^{-7} \, \text{H/m} \) or \( 4 \times 10^{-7} \, \text{H/m} \) for simplicity. ...
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