If the electric current through an electric bulb is 4.8 A, then the number of electrons flowing through it in 2 seconds is

Options

A. `2 xx 10^(19)`
B. `6 xx 10^19`
C. `3 xx 10^19`
D. `5 xx 10^19`

Explanation

To solve the problem of finding the number of electrons flowing through an electric bulb when the electric current is 4.8 A for a duration of 2 seconds, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between current, charge, and time**:
The electric current (I) is defined as the rate of flow of charge (Q) over time (t). The formula for this relationship is:
\[ I = \frac{Q}{t} \]
Rearranging this formula gives us:
\[ Q = I \times t \]

2. **Substitute the given values**:
We know the current \( I = 4.8 \, \text{A} \) and the time \( t = 2 \, \text{s} \). Now we can calculate the total charge:
\[ Q = 4.8 \, \text{A} \times 2 \, \text{s} = 9.6 \, \text{C} \]

3. **Use the charge of an electron**:
The charge of a single electron is approximately \( e = 1.6 \times 10^{-19} \, \text{C} \). To find the number of electrons (n) that correspond to the total charge (Q), we use the formula:
\[ n = \frac{Q}{e} \]

4. **Calculate the number of electrons**:
Substitute the values we have:
\[ n = \frac{9.6 \, \text{C}}{1.6 \times 10^{-19} \, \text{C}} = 6 \times 10^{19} \]

5. **Conclusion**:
The number of electrons flowing through the bulb in 2 seconds is \( 6 \times 10^{19} \).

### Final Answer:
The number of electrons flowing through the electric bulb in 2 seconds is \( 6 \times 10^{19} \).

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