A potential difference of 100 V is applied to the ends of a copper wire one metre long.
What is the magnitude of electric field produced ?

Options

A. `100 Vm^(-1)`
B. `20 Vm^(-1)`
C. `10 Vm^(-1)`
D. `25 Vm^(-1)`

Explanation

To solve the problem of finding the magnitude of the electric field produced when a potential difference of 100 V is applied across a copper wire of length 1 meter, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Potential difference (V) = 100 V
- Length of the wire (L) = 1 m

2. **Recall the formula for electric field (E):**
The electric field (E) produced in a conductor can be calculated using the formula:
\[ E = \frac{V}{L} \]
where:
- \( E \) is the electric field in volts per meter (V/m),
- \( V \) is the potential difference in volts (V),
- \( L \) is the length of the conductor in meters (m).

3. **Substitute the values into the formula:**
\[ E = \frac{100 \, \text{V}}{1 \, \text{m}} = 100 \, \text{V/m} \]

4. **Conclusion:**
The magnitude of the electric field produced is:
\[ E = 100 \, \text{V/m} \]

### Final Answer:
The magnitude of the electric field produced is **100 V/m**.

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