A body has a negative charge of `16xx10^(-19)` C it has:

Options

A. an excess of 5 electrons
B. an excess of 10 electrons
C. a deficiency of 16 electrons
D. a deficiency of 8 electrons

Explanation

To solve the problem of determining the number of excess electrons in a body with a negative charge of \( 16 \times 10^{-19} \) C, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Charge of an Electron**:
The charge of a single electron is approximately \( 1.6 \times 10^{-19} \) C. This is a fundamental constant in physics.

2. **Identify the Total Charge**:
The body has a total charge of \( -16 \times 10^{-19} \) C. The negative sign indicates that the body has an excess of electrons.

3. **Calculate the Number of Excess Electrons**:
To find the number of excess electrons, we can use the formula:
\[ \text{Number of electrons} = \frac{\text{Total charge}}{\text{Charge of one electron}} \]
Substituting the values:
\[ \text{Number of electrons} = \frac{-16 \times 10^{-19} \, \text{C}}{-1.6 \times 10^{-19} \, \text{C/electron}} \]

4. **Perform the Calculation**:
The negatives cancel out:
\[ \text{Number of electrons} = \frac{16 \times 10^{-19}}{1.6 \times 10^{-19}} = \frac{16}{1.6} = 10 \]

5. **Conclusion**:
The body has an excess of 10 electrons.

### Final Answer:
The body has an excess of 10 electrons.

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