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A positive charge Q kept at the centre o...

A positive charge Q kept at the centre of a square PQRS having four charges are arranged at the corners as shown in the figure. The force on the charge Q.

A

`(2Qq)/(4piepsi_0)`

B

`(Qq)/(4piepsi_0)`

C

0

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`(2Qq)/(4piepsi_0)`
Explanation: Forces `F_"OA" and F_"OC"` are equal and opposite to each other. So they will cancel out.
`F_"net"=F_"OD"+F_"OB"`
`=1/(4piepsi)[(Qq)/1^2+(Qq)/1^2]`
`=(2Qq)/(4piepsi_0)`
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