Two point charges (+2q) and (-2q) are kept inside a large metallic cube without touching its sides. Electric flux emerging out of the cube is:

Options

A. `(4q)/(epsi_0)`
B. `(2q)/(epsi_0)`
C. 0
D. `q/(epsi_0)`

Explanation

To solve the problem of finding the electric flux emerging out of a large metallic cube containing two point charges (+2q) and (-2q), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Charges Inside the Cube**:
- We have two point charges: one is +2q and the other is -2q.

2. **Apply Gauss's Law**:
- Gauss's Law states that the electric flux (Φ) through a closed surface is proportional to the net charge (Q_enc) enclosed within that surface. The formula is given by:
\[ \Phi = \frac{Q_{enc}}{\epsilon_0} \]
- Here, \( \epsilon_0 \) is the permittivity of free space.

3. **Calculate the Net Charge Inside the Cube**:
- The net charge inside the cube is calculated by summing the individual charges:
\[ Q_{enc} = (+2q) + (-2q) = 0 \]

4. **Substitute the Net Charge into Gauss's Law**:
- Since the net charge \( Q_{enc} \) is zero, we substitute this into Gauss's Law:
\[ \Phi = \frac{0}{\epsilon_0} = 0 \]

5. **Conclusion**:
- The electric flux emerging out of the cube is zero.

### Final Answer:
The electric flux emerging out of the cube is **0**.