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Five resistance are connected as shown i...

Five resistance are connected as shown in figure. The equivalent resistance between point A and B is:

A

`(14)/(3Omega)`

B

`14Omega`

C

`3/(14Omega)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

`(14)/(3Omega)`
Explanation: When bridge is balanced, then there is no current flow through `12Omega` resistance.
`therefore" "R_1/R_2=R_3/R_4`
`rArr(4Omega)/(8Omega)=(3Omega)/(6Omega)`
`rArr1/2=1/2`
`therefore` Bridge is balanced.
Now, `R_1 and R_3` are connected in series, `R_2 and R_4` are in series combination
`R.=R_1+R_3`
`=4+3`
`=7Omega`
`R..=R_2+R_4`
`=8+6`
`14Omega`
Again, R. and R.. in parallel
`therefore" "1/R_"AB"=1/(R.)+1/(R..)`
`rArr" "R_"AB"=(R.R..)/(R.+R..)`
`=(7xx14)/(14+7)=(98)/(21)=(14)/(3Omega)`
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