The resistance of a wire is given by `100Omega`
The specific resistance of wire of length 1 m and area 2 `m^2` is:

Options

A. `100Omega-m`
B. `200Omega-m`
C. `300Omega-m`
D. `400Omega-m`

Explanation

To find the specific resistance (also known as resistivity) of the wire, we can use the formula that relates resistance (R), specific resistance (ρ), length (L), and cross-sectional area (A) of the wire:

\[ R = \frac{\rho \cdot L}{A} \]

Where:
- \( R \) is the resistance of the wire (in ohms, Ω)
- \( \rho \) is the specific resistance (in ohm-meters, Ω·m)
- \( L \) is the length of the wire (in meters, m)
- \( A \) is the cross-sectional area of the wire (in square meters, m²)

Given:
- \( R = 100 \, \Omega \)
- \( L = 1 \, m \)
- \( A = 2 \, m^2 \)

We need to rearrange the formula to solve for specific resistance (ρ):

\[ \rho = \frac{R \cdot A}{L} \]

Now, substituting the given values into the equation:

\[ \rho = \frac{100 \, \Omega \cdot 2 \, m^2}{1 \, m} \]

Calculating the right side:

\[ \rho = \frac{200 \, \Omega \cdot m^2}{1 \, m} = 200 \, \Omega \cdot m \]

Thus, the specific resistance of the wire is:

\[ \rho = 200 \, \Omega \cdot m \]

### Final Answer:
The specific resistance of the wire is \( 200 \, \Omega \cdot m \).

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