`(7+sqrt-4)(7-sqrt-4)=?`

(sqrt4)^-7(sqrt2)^-5

(1)/(sqrt(9)-sqrt(8))-(1)/(sqrt(8)-sqrt(7))+(1)/(sqrt(7)-sqrt(6))-(1)/(sqrt(6)-sqrt(5))+(1)/(sqrt(5)-sqrt(4))=?

If a=sqrt((7+4sqrt(3))/(7-4sqrt(3))) then the value of [a(a-14)]^(2) is

(sqrt7-sqrt6)/(sqrt7+sqrt6)-(sqrt7+sqrt6)/(sqrt7-sqrt6)=

The square root of (7+3sqrt(5))(7-3sqrt(5)) is sqrt(5)(b)2(c)4(d)3sqrt(5)

The square root of (7+3sqrt5) (7-3sqrt5) is (A) 4 (B) sqrt5 (C) 3sqrt5 (D) 2

sqrt(7+4sqrt3) - sqrt(7-4sqrt3) =

By how much does 5sqrt(7) - 2sqrt(5) exceed 3sqrt(7) - 4sqrt(5) ?