25.Sulphur is more stable in the form of...

25.Sulphur is more stable in the form of rhombic sulphur which contains S_(8) rings. This on heating converts into vapour that consists of S_(2) fragments. The correct statements about these S_(8) and S_(2) molecules. A) S -S bond length is more in S_(8) than in S_(2) . B) S_(8) ring is diamagnetic whereas S_(2) is paramagnetic. C) ln S_(8) and S_(2) molecules there are two lone pairs of electrons on each sulphur atom D) Both gives same product on burning.

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In S_(8) each sulphur atom is :-

is sulphur S_(2) is paramagnetic in nature and why ?

The oxidation number of sulphur in H_(2)S_(2)O_(8) is:

Assertion: In vapour state sulphur is paramagnetic in nature. Reason : In vapour state sulphur exists as S_(2) molecule.

Comment on the nature of two S–O bonds formed in SO_(2) molecule. Are the two S–O bonds in this molecule equal ?

Write the formula of the compound of sulphur which is obtained when conc. HNO_(3) oxidises S_(8) .

How many S-S bonds are present in S_8 molecule ?

The oxidation state of S in H_(2)S_(2)O_(8) is

The oxidation state of S in S_(8) is zero.

Sulphur does not exist as S_2 molecule because