(i) `sqrt3(sqrt7-sqrt3)`

(iii) (sqrt 5+ sqrt 3)/(sqrt5-sqrt3)+(sqrt5-sqrt3)/(sqrt5+sqrt3) =?

solve (3sqrt5 +sqrt3)/(sqrt5 -sqrt3)

Solve: (sqrt 3+ sqrt2)(sqrt2-sqrt3)

1/(sqrt(7)+sqrt(3))\times (sqrt(7)-sqrt(3))/(sqrt(7)-sqrt(3))

(sqrt(7)+2sqrt(3))(sqrt(7)-2sqrt(3))

Simplify (7sqrt3)/(sqrt10+sqrt3)-(2sqrt5)/(sqrt6+sqrt5)-(3sqrt2)/(sqrt15+3sqrt2)

(sqrt5 - sqrt3)/(sqrt5 + sqrt3) is equal to :

If x= ( sqrt5- sqrt3)/ ( sqrt5+ sqrt3) and y= ( sqrt5+ sqrt3)/( sqrt5- sqrt3) find the value of x^(2) + y ^(2)

Let k be a real number such that the inequality sqrt(x-3) +sqrt(6 -x) ge k has a solution then the maximum value of k is sqrt3 (2) sqrt6 -sqrt3 (3) sqrt6 (4) sqrt6 +sqrt3

Find: (sqrt7 +sqrt3)(3-sqrt3)