`int_(0)^( pi/2)(sinx-cosx)dx`

Evaluate int_(0)^(pi//2)|sinx-cosx|dx .

show that int_(0)^(pi//2)(sinx-cosx)log(sinx+cosx)dx=0

int_(0)^(pi//2)(sinx-cosx)log(sinx+cosx)dx=0

Evaluate int_(0)^(pi//2)(sinx-cosx)/(1+sinx*cosx)dx

I_(1)=int_(0)^((pi)/2)(sinx-cosx)/(1+sinxcosx)dx, I_(2)=int_(0)^(2pi)cos^(6)dx , I_(3)=int_(-(pi)/2)^((pi)/2)sin^(3)xdx, I_(4)=int_(0)^(1) In (1/x-1)dx . Then

Evaluate: int_0^(pi/2)|sinx-cosx|dx

Evaluate: int_0^(pi//2)x/(sinx+cosx)dx

int_(0)^(pi//2)(x)/(sinx+cosx)dx .

The value of int_(0)^(pi//2)(asinx+bcosx)/(sinx+cosx)dx is equal to

Let I_(n)=int_(0)^(pi//2)(sinx+cosx)^(n)dx(nge2) . Then the value of n. I_(n)-2(n-1)I_(n-1) is