If `0` < `x` < `pi` the matrix `[[4sinx,-1],[-3,sinx]]` is singular, then the value of `x` are:
A.`pi/3`,` (2pi) /3`
B.`pi/6`,`(5pi)/6`
C.`pi/6`,`pi/3`
D.`pi/6`,`(2pi)/3`

The possible values of theta in (0,pi) such that sin (theta) + sin (4theta) + sin(7theta) = 0 are (1) (2pi)/9 , i/4 , (4pi)/9, pi/2, (3pi)/4 , (8pi)/9 (2) pi/4, (5pi)/12, pi/2 , (2pi)/3, (3pi)/4, (8pi)/9 (3) (2pi)/9, pi/4 , pi/2 , (2pi)/3 , (3pi)/4 , (35pi)/36 (4) (2pi)/9, pi/4, pi/2 , (2pi)/3 , (3pi)/4 , (8pi)/9

The possible values of theta in (0,pi) such that sin (theta) + sin (4theta) + sin(7theta) = 0 are (1) (2pi)/9 , i/4 , (4pi)/9, pi/2, (3pi)/4 , (8pi)/9 (2) pi/4, (5pi)/12, pi/2 , (2pi)/3, (3pi)/4, (8pi)/9 (3) (2pi)/9, pi/4 , pi/2 , (2pi)/3 , (3pi)/4 , (35pi)/36 (4) (2pi)/9, pi/4, pi/2 , (2pi)/3 , (3pi)/4 , (8pi)/9

If t a nalpha=5/2 , tanbeta=-7/9 where alpha in [pi/2,pi] , then alpha+beta lies in the interval. [(3pi)/2,(7pi)/3] (b) [(13pi)/6,(5pi)/2] [(13pi)/6,(7pi)/3] (d) [pi/6,pi/3]

If log_10(sin x) + log_10(tany)+ log_10 2=0 and coty= 2sqrt3 cos x, then ordered pair (x, y) satisfying the equations simultaneously is(are) (A) (pi/3 ,pi/3) (B) (pi/3 ,pi/6) (C) (pi/6 ,(2pi)/3) (D) (pi/3 , (7pi)/6)

If roots of the equation 2x^2-4x+2sintheta-1=0 are of opposite sign, then theta belongs to (pi/6,(5pi)/6) (b) (0,pi/6)uu((5pi)/6,pi) ((13pi)/6,(17pi)/6) (d) (0,pi)

In which of the following sets the inequality sin^6x+cos^6x >5/8 holds good? (a) (-pi/3,pi/8) (b) ((3pi)/8,(5pi)/8) (c) (pi/4,(3pi)/4) (d) ((7pi)/8,(9pi)/8)

cos^-1 {-sin((5pi)/6)}= (A) - (5pi)/6 (B) (5pi)/6 (C) (2pi)/3 (D) -(2pi)/3

Given both thetaa n dphi are acute angles and sintheta=1/2,cosvarphi=1/3, then the value of theta+varphi belongs to (a) (pi/3,pi/2] (b) (pi/2,(2pi)/3] (c) ((2pi)/3,(5pi)/6] (d) ((5pi)/6,pi]

For 0 cos^(-1)(sintheta) is true when theta belongs to (a) (pi/4,pi) (b) (pi,(3pi)/2) (c) (pi/4,(3pi)/4) (d) ((3pi)/4,2pi)

The value of theta in (0,2pi) for which 2sin^2theta-5sintheta+2>0 is (0,pi/6)uu((5pi)/6,2pi) (b) (pi/8,(pipi)/6) (0,pi/8)uu(pi/6pi/6) (d) ((41pi)/(48),pi)