38. For A=[[3,1],[-1,2]],then 14A^(-1) i...

38. For `A=[[3,1],[-1,2]]`,then `14A^(-1)` is given by:
a) `14[[2,-1],[1,3]]`
,b) `[[4,-2],[2,6]]`
c) `2[[2,-1],[1,3]]`,
d) `2[[-3,-1],[1,-2]]`

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