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dy/dx=sinx/cosx...

`dy/dx=sinx/cosx`

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Find dy/dx if y= sinx/cosx

ysinx dy/dx=(sinx-y^2)cosx

If y=(sinx)/(x+cosx) , then find (dy)/(dx) .

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If y=sqrt(cosx+sqrt(cosx+sqrt(cosx+\ dotto\ oo))) , prove that (dy)/(dx)=(sinx)/(1-2y) .

dy/dx=-(cosx(3cosy-7sinx-3))/(siny(3sinx-7cosy+7))

dy/dx-y = cosx

dy/dx - y = cosx

find dy/dx if y= sinx.cosx

Find dy/dx if y= sinx.cosx