`int_(1)^(infinity)(ln(x-1))/(x^(2) (ln x)^()-ln x(ln(x-1)) )dx (A) (1)/(2) (B) (1)/(3) (C) 0`

If int_(0)^(1) (log(1+x)/(1+x^(2))dx=

int_(1)^(2) (dx)/(x(1+log x)^(2))

int(tan(1+log x))/(x) dx

int_(1)^(3) (dx)/(x^(2)(x+1))=(2)/(3)+log .(2)/(3)

int(log(x+1)-log x)/(x(x+1))dx= (A) log(x-1)log x+(1)/(2)(log x-1)^(2)-(1)/(2)(log x)^(2)+c (B) (1)/(2)(log(x+1))^(2)+(1)/(2)(log x)^(2)-log(x+1)log x+c (C) -(1)/(2)(log(x+1)^(2))-(1)/(2)(log x)^(2)+log x*log(x+1)+c (D) [log(1+(1)/(x))]^(2)+c

Evaluate : int_(0)^(1)(log(1+x))/(1+x^2)dx

Evaluate int_(0)^(1)(ln(1+x))/(1+x)dx

int_(0)^(log 2)(e^(x))/(1+e^(x))dx=

int ln(1+x)^(1+x)dx

solve int_(1)^(2)(log x)/(x^(2))dx