`int_(0)^(1)x tan^(-1)xdx`

I=int_(0)^(1)tan^(-1)xdx

If int_(0)^(1) cot^(-1)(1-x+x^(2))dx=k int_(0)^(1) tan^(-1)x dx , then k=

Solve: int_(-1)^(1)x tan^(-1)x dx

Let J=int_(0)^(1)cot^(-1)(1-x+x^(2))dx and K= int_(0)^(1)tan^(-1)xdx .If J=lambda K (lambda in N) , then lambda equals

STATEMENT-1 : int_(-3)^(3)|x|dx=9 STATEMENT-2 : int_(0)^(1)tan^(-1)xdx=(pi)/(4)-lnsqrt(2) STATEMENT-3 : int_(0)^(pi//2)(sqrt(cosx))/(sqrt(sinx)+sqrt(cosx))dx=(pi)/(4)

Evaluate: int_0^1xtan^(-1)xdx

int_(0)^( pi)x sin^(-1)xdx

The value of int_(0)^(1) tan^(-1)((2x-1)/(1+x-x^(2)))dx is

int _(0)^(1) (tan ^(-1)x)/(x ) dx =

int_(0)^(1) ( tan^(-1)x)/( 1+x^(2)) dx is equal to